Value of Sin pi — sin(π) in Radians & Unit Circle

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Value of Sin pi — sin(π) in Radians & Unit Circle

TL;DR

The value of sin pi is 0. In radians, π corresponds to 180° — half a full rotation around the unit circle. The point on the unit circle at this angle is (−1,0). Since sine reads the y-coordinate of that point, sin⁡π=0.

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Bhanzu Team Last updated on May 20, 2026 9 min read

A Half Rotation Lands You Back on the Axis

A full rotation around a circle returns you to your starting point. Half a rotation — π radians, or 180° — lands you on the opposite side, but if your starting point was on the horizontal axis, your vertical position is the same: zero. That's the entire story of sin⁡π=0: the half-rotation keeps you on the horizontal axis, and sine reads the vertical coordinate.

What Is sin pi?

sin⁡π is the sine of the angle π radians, equivalent to sin⁡(180°). Its value is:

sin⁡π=0

This is one of the foundational exact values in trigonometry — alongside sin⁡0=0, sin⁡(π/2)=1, sin⁡(π/6)=1/2, sin⁡(π/4)=√2/2, and sin⁡(π/3)=√3/2.

Three Methods to Find sin pi

Method 1 — Unit Circle

On the unit circle (radius 1, centred at the origin), the point at angle θ has coordinates (cos⁡θ,sin⁡θ).

The angle π corresponds to half a rotation — landing on the point (−1,0).

So sin⁡π=0 (the y-coordinate) and cos⁡π=−1 (the x-coordinate).

Method 2 — From the Sine Graph

The sine curve has these zeros: x=0,π,2π,3π,… and x=−π,−2π,… . More precisely, sin⁡x=0 for every integer multiple of π.

Reading the graph at x=π: sin⁡π=0.

Method 3 — Using the Supplementary-Angle Identity

The identity sin⁡(π−θ)=sin⁡θ holds for every θ. Setting θ=0:

sin⁡π=sin⁡(π−0)=sin⁡0=0.

Three independent methods, same answer. The agreement is the whole point of identities — they make the value un-mistakable.

Unit Circle Sine Reference — All Standard Angles

The complete sine values around the unit circle, organised by quadrant:

Angle (radians) Angle (degrees) sin⁡θ Quadrant
0 0 Axis
π/6 30° 1/2 I
π/4 45° √2/2 I
π/3 60° √3/2 I
π/2 90° 1 Axis
2π/3 120° √3/2 II
3π/4 135° √2/2 II
5π/6 150° 1/2 II
π 180° 0 Axis
7π/6 210° −1/2 III
5π/4 225° −√2/2 III
4π/3 240° −√3/2 III
3π/2 270° −1 Axis
5π/3 300° −√3/2 IV
7π/4 315° −√2/2 IV
11π/6 330° −1/2 IV
360° 0 Axis

Pattern lock-in.

Sine is positive in quadrants I and II (upper half of the circle), negative in III and IV (lower half), and zero on the horizontal axis (0, π, 2π). The four "axis" angles — 0, π/2, π, 3π/2 — give the four "extreme" sine values: 0, 1, 0, −1.

sin pi in Terms of Other Trigonometric Functions

The full set of trig function values at θ=π:

sin⁡π=0, cos⁡π=−1, tan⁡π=0, csc⁡π=undefined (division by zero), sec⁡π=−1, cot⁡π=undefined (division by zero).

Two of the six are undefined because sin⁡π=0 appears in the denominator. The angle π is a "node" — a point where the wave passes through zero.

Three Worked Examples — Quick, Standard, Stretch

Quick

Evaluate sin⁡π+cos⁡π.

sin⁡π=0 and cos⁡π=−1.

sin⁡π+cos⁡π=0+(−1)=−1.

A Common Slip Worth Walking Through — Standard Example

Evaluate sin⁡(2π/3)+sin⁡π+sin⁡(7π/6).

The wrong path. A student reasons: "sin⁡(2π/3) is in quadrant II — positive. sin⁡π=0. sin⁡(7π/6) is in quadrant III — negative. So the answer is sin⁡(2π/3)+0+sin⁡(7π/6)=sin⁡(60°)−sin⁡(30°)."

Wait — what are the reference angles?

Sanity check. 2π/3=120°, so its reference angle is π−2π/3=π/3=60°. That's right. 7π/6=210°, so its reference angle is 7π/6−π=π/6=30°. That's right. So sin⁡(7π/6)=−sin⁡(π/6)=−1/2, and the answer is 3/2+0+(−1/2)=(3−1)/2.

Stretch

A pendulum's vertical displacement is y(t)=0.3sin⁡(πt). Where is the pendulum at t=1,2,3 seconds?

At t=1: y(1)=0.3sin(π)=0.3⋅0=0 m.

At t=2: y(2)=0.3sin(2π)=0.3⋅0=0 m.

At t=3: y(3)=0.3sin(3π)=0.3⋅0=0 m.

At every integer value of t, the pendulum is at y=0 — its equilibrium position. The period is 2 seconds (so the pendulum returns to y=0 every 1 second).

Where sin pi = 0 Quietly Powers the World

sin⁡π=0 may look trivial, but its periodic cousin sin⁡(nπ)=0 is the foundation of every oscillation, wave, and Fourier-series analysis.

Where Things Go Sideways — Common Mistakes

Mistake 1: Confusing sin⁡π with sin⁡(π°)

Don't do this: Computing sin⁡π in degree mode.

Mistake 2: Reading sin⁡π as sin⁡sin × π

Don't do this: Writing "sin⁡π=π" because the symbols look juxtaposed.

Mistake 3: Thinking sin⁡ of any small fraction of π must be small

Don't do this: Assuming sin⁡(3π/7)≈0 because "3π/7 is close to π".

Key Takeaways

Take Sin pi for a Test Drive — Three Problems

  1. Evaluate sin⁡π+sin⁡(2π)+sin⁡(3π).
  2. Find sin⁡(5π/4) using the unit-circle table above.
  3. Show that sin⁡π⋅cos⁡(π/2)+cos⁡π⋅sin⁡(π/2)=-1.

If #1 didn't give you 0, re-check that sine is zero at every integer multiple of π. If #2 didn't give you −√2/2, look at the table — 5π/4 is in quadrant III.

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