Vector Form - Definition, Formula, and Examples

Vector Form - Definition, Formula, and Examples

What Is Vector Form?

Vector form is a way of writing the equation of a line (or a plane) using vectors instead of plain x and y coordinates. A vector is a quantity with both size and direction, drawn as an arrow; if you need the basics first, see what is a vector and the fuller treatment of vectors.

The core idea is simple. To pin down a straight line, you only need two things:

From there, every point on the line is reachable by starting at (\vec{a}) and travelling some multiple of (\vec{b}). That multiple is the scalar (\lambda) (lambda), and it can be any real number - positive, negative, or zero.

[ \vec{r} = \vec{a} + \lambda \vec{b} ]

As (\lambda) changes, (\vec{r}) sweeps out every point on the line. Set (\lambda = 0) and you are back at (\vec{a}); set (\lambda = 1) and you have moved one full direction-vector along; make (\lambda) negative and you travel backwards.

The two standard forms

There are two ways a line is usually written in vector form, and both are the same formula wearing different clothes.

Through a point, parallel to a direction:

[ \vec{r} = \vec{a} + \lambda \vec{b} ]

where (\vec{a}) is the position vector of a known point and (\vec{b}) is the direction vector.

Through two known points with position vectors (\vec{a}) and (\vec{c}):

[ \vec{r} = \vec{a} + \lambda (\vec{c} - \vec{a}) ]

Here the direction vector is built by subtracting the two points, (\vec{c} - \vec{a}), which is the arrow pointing from the first point to the second. This is why the vector concepts, parallel vectors and the position vector, are essential in vector form: the direction (\vec{b}) is direction, and (\vec{a}) is a position.

How vector form links to parametric and Cartesian forms

Vector form is not a rival to the equations you already know - it is their parent. Write (\vec{r} = (x,y,z)), (\vec{a} = (a_1,a_2,a_3)), and (\vec{b} = (b_1,b_2,b_3)), then read off one coordinate equation per axis:

[ x = a_1 + \lambda b_1 ] [ y = a_2 + \lambda b_2 ] [ z = a_3 + \lambda b_3 ]

Those three lines are the parametric form - the same line, written coordinate by coordinate. Eliminate (\lambda) from them and you get the Cartesian (symmetric) form. All three describe the identical set of points; vector form is just the most compact.

Form Looks like Best for
Vector (\vec{r} = \vec{a} + \lambda \vec{b}) compact, works in 3D
Parametric (x = a_1 + \lambda b_1), etc. plugging in a parameter
Cartesian (\frac{x - a_1}{b_1} = \frac{y - a_2}{b_2} = \frac{z - a_3}{b_3}) no parameter, direct relation

Examples Of Vector Form

These build from writing a line up to finding where a point sits on it. One of them shows a wrong turn worth walking through.

Example 1

Write the vector equation of a line passing through the point (2,3) with direction vector (\vec{b}=4\hat{i}+5\hat{j}).

The position vector of the point is (\vec{a}=2\hat{i}+3\hat{j}). Slot both into the standard form.

[ \vec{r} = \vec{a} + \lambda \vec{b} ] [ \vec{r} = (2\hat{i}+3\hat{j}) + \lambda(4\hat{i}+5\hat{j}) ]

That is the vector equation of the line.

Example 2

Write the vector equation of the line through the two points A(1,2,3) and C(4,5,6).

The tempting move is to add the two position vectors to get a direction: (\vec{a} + \vec{c} = (1+4,2+5,3+6)=(5,7,9)), then write (\vec{r} = \vec{a} + \lambda(5,7,9)).

That is wrong, and here is the tell: adding two positions gives a point that is roughly "between and beyond" the two, not the direction from one to the other. A direction must describe travel, so it comes from subtraction, not addition.

The correct direction vector is (\vec{c} - \vec{a}):

[ \vec{c} - \vec{a} = (4 - 1, 5 - 2, 6 - 3) = (3, 3, 3) ]

So the line is

[ \vec{r} = (1, 2, 3) + \lambda(3, 3, 3) ]

Check it: (\lambda=0) gives A(1,2,3) and (\lambda=1) gives (4,5,6)=C. Both endpoints land, so the direction was right.

Example 3

Find the point on the line (\vec{r} = (1,0,2)+\lambda(2,1,3)) when (\lambda=2).

Substitute (\lambda=2) and compute each coordinate:

[ x = 1 + 2(2) = 5 ] [ y = 0 + 1(2) = 2 ] [ z = 2 + 3(2) = 8 ]

The point is (5,2,8).

Example 4

Convert the vector equation (\vec{r} = (3,-1)+\lambda(2,4)) into parametric form.

Read off one equation per coordinate:

[ x = 3 + 2\lambda ] [ y = -1 + 4\lambda ]

These are the parametric form of the same line.

Example 5

Is the point (7,7) on the line (\vec{r} = (1,3)+\lambda(3,2))?

Write the parametric equations and solve for (\lambda) from one coordinate:

For x: [ 7 = 1 + 3\lambda \Rightarrow \lambda = 2 ]

Then check y: [ 3 + 2(2) = 7 ]

Both coordinates satisfy, so yes, (7,7) lies on the line.

Example 6

Give the direction vector of the line (\vec{r}=(0,4,-2)+\lambda(5,-3,1)), and state whether (10,-2,0) is on it.

The direction vector is (\vec{b}=(5,-3,1)). Test the point coordinate by coordinate:

All three match at (\lambda = 2), so (10,-2,0) is on the line.

Why Vector Form Matters - "The Only Line Equation That Survives In 3D"

Vector form exists because the school-favourite (y = mx + c) quietly fails the moment you leave a flat page. In three dimensions, there is no single "slope" for a line, and a vertical line has no slope at all. Vector form sidesteps both problems.

Mistakes To Watch For With Vector Form

Mistake 1: Adding two points instead of subtracting for the direction

Where it slips in: finding the vector equation of a line through two given points.
Don't do this: use (\vec{a} + \vec{c}) as the direction vector.
The correct way: the direction from point A to point C is (\vec{c} - \vec{a}), always a subtraction.

Mistake 2: Treating the position vector as the direction (or vice versa)

Where it slips in: reading a line written as (\vec{r} = \vec{a} + \lambda \vec{b}).
Don't do this: call (\vec{a}) the direction and (\vec{b}) the point. The correct way: (\vec{a}) is the position of a known point; (\vec{b}) is the direction.

Mistake 3: Thinking different equations mean different lines

Where it slips in: comparing your answer to a textbook's when both use different points or a scaled direction.
Don't do this: assume (\vec{r}=(1,2,3)+\lambda(3,3,3)) and (\vec{r}=(4,5,6)+\mu(1,1,1)) are different lines.
The correct way: a line's vector equation is not unique - any point on the line works as (\vec{a}), and any scalar multiple of (\vec{b}) works as the direction.

Key Takeaways