Eccentricity of an Ellipse: Formula, Meaning, Examples

Eccentricity of an Ellipse: Formula, Meaning, Examples

TL;DR

The eccentricity of an ellipse is a single number, e, that measures how stretched the ellipse is, from a perfect circle to a long, thin oval. This article covers what eccentricity measures, the two equivalent formulas, why it always lies between 0 and 1, the derivation, and worked examples.

What Does the Eccentricity of an Ellipse Measure?

The eccentricity of an ellipse measures how far the ellipse is from being a circle, in other words, how elongated or "squashed" it is. It is written e and defined as the ratio of two lengths:

e = \frac{c}{a},

where c is the distance from the center to a focus (one of the two fixed points that define the ellipse), and a is the semi-major axis, half the length of the long axis. A larger e means the foci sit farther from the center relative to the ellipse's size, which means a more stretched curve.

Because both c and a are lengths and c is always smaller than a for an ellipse, the ratio always lands strictly between 0 and 1:

0 < e < 1.

The two endpoints tell the story. At e = 0, the two foci have merged at the center and the ellipse is a perfect circle. As e climbs toward 1, the foci slide out toward the vertices and the ellipse stretches into a long, thin shape.

The Eccentricity of an Ellipse Formula

There are two formulas, and they are the same statement in two outfits. The first uses the focal distance directly:

e = \frac{c}{a}.

The second avoids c entirely, expressing eccentricity from just the two axes:

e = \sqrt{1 - \frac{b^2}{a^2}},

where b is the semi-minor axis, half the short axis. You reach for the first formula when you already know c (or the foci), and the second when you only have the equation \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 and can read off a^2 and b^2.

The two are connected by the focal relationship c^2 = a^2 - b^2, which holds for every ellipse, the foci sit inside, so c is always shorter than a.

Where the Second Formula Comes From

The formula e = \sqrt{1 - \frac{b^2}{a^2}} is not a separate fact to memorize. It falls straight out of e = \frac{c}{a} once you bring in the focal relationship c^2 = a^2 - b^2.

Start from the definition and square it to clear the square root that c will introduce:

e = \frac{c}{a}; \Rightarrow; e^2 = \frac{c^2}{a^2}.

Substitute c^2 = a^2 - b^2:

e^2 = \frac{a^2 - b^2}{a^2} = 1 - \frac{b^2}{a^2}.

Take the positive square root (eccentricity is a length ratio, so it is positive):

e = \sqrt{1 - \frac{b^2}{a^2}}.

This also shows why 0 < e < 1 falls out for free. Since b < a, the fraction \frac{b^2}{a^2} is a positive number less than 1, so 1 - \frac{b^2}{a^2} sits between 0 and 1, and its square root does too. When b = a, the ellipse is a circle and e = 0; the foci can never reach the vertices, so e never actually hits 1.

Where the Eccentricity of an Ellipse Shows Up

Eccentricity is the number scientists and engineers actually quote when they describe an orbit, a lens, or an antenna, because it captures the shape's character in one figure, independent of size.

For a Class 11 student, eccentricity is where a static equation turns into a description you can picture: hand someone e = 0.9 and they already know the curve is long and thin before drawing a thing.

Examples of the Eccentricity of an Ellipse

Example 1

Find the eccentricity of the ellipse \frac{x^2}{25} + \frac{y^2}{16} = 1.

Here a^2 = 25 (the larger denominator) and b^2 = 16. Use the axis-only formula:

e = \sqrt{1 - \frac{b^2}{a^2}} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5} = 0.6.

The eccentricity is 0.6, moderately stretched, well clear of a circle.

Example 2

Find the eccentricity of the ellipse \frac{x^2}{9} + \frac{y^2}{25} = 1.

A natural first move is to assume a^2 is the number under x^2, so take a^2 = 9 and b^2 = 25, then compute e = \sqrt{1 - \frac{25}{9}} = \sqrt{-1.78}. That impossibility is the signal: e is a real number between 0 and 1, so a negative inside the root means the labels are swapped.

The fix: a is always the semi-major axis, so a^2 is the larger denominator. Here 25 is larger, so the major axis is vertical, a^2 = 25 and b^2 = 9:

e = \sqrt{1 - \frac{9}{25}} = \sqrt{\frac{16}{25}} = \frac{4}{5} = 0.8.

The eccentricity is 0.8.

Example 3

An ellipse has semi-major axis a = 13 and focal distance c = 5. Find its eccentricity.

Here c is given directly, so use the first formula:

e = \frac{c}{a} = \frac{5}{13} \approx 0.385.

The eccentricity is about 0.385, fairly close to circular.

Example 4

Find the eccentricity of the ellipse \frac{x^2}{36} + \frac{y^2}{11} = 1.

With a^2 = 36 and b^2 = 11:

e = \sqrt{1 - \frac{11}{36}} = \sqrt{\frac{25}{36}} = \frac{5}{6} \approx 0.833.

The eccentricity is about 0.833, a noticeably elongated ellipse.

Example 5

An ellipse has eccentricity e = 0.6 and semi-major axis a = 10. Find its semi-minor axis b.

Work the formula backwards. From e = \frac{c}{a}, the focal distance is c = 0.6 \times 10 = 6. Then use c^2 = a^2 - b^2:

b^2 = a^2 - c^2 = 100 - 36 = 64; \Rightarrow; b = 8.

The semi-minor axis is 8.

Example 6

Earth's orbit has eccentricity about 0.017, and Halley's Comet about 0.967. Interpret each.

No computation, just reading. Earth's e = 0.017 is almost 0, so its orbit is very nearly a circle, the Sun (at one focus) is only slightly off-center. Halley's e = 0.967 is very close to 1, so its orbit is a long, thin ellipse, the comet races close to the Sun, then drifts far out before returning.

The interpretation: eccentricity alone tells you the character of the orbit. A single decimal separates a gentle near-circle from a dramatic, stretched sweep.

Where Students Trip Up on the Eccentricity of an Ellipse

Mistake 1: Mislabelling which axis is the major axis

Where it slips in: Reading a^2 and b^2 off the equation when the larger denominator is under y^2.

Don't do this: Always assign a^2 to the number under x^2.

The correct way: a is the semi-major axis, so a^2 is always the larger denominator. If 1 - \frac{b^2}{a^2} comes out negative, you have swapped them.

Mistake 2: Forgetting the square root

Where it slips in: Using the second formula and stopping at 1 - \frac{b^2}{a^2}.

Don't do this: Report e = 1 - \frac{b^2}{a^2}; that quantity is e^2, not e.

The correct way: The formula is e = \sqrt{1 - \frac{b^2}{a^2}}. The square root is not optional; dropping it gives the square of the eccentricity.

Mistake 3: Treating eccentricity as a length

Where it slips in: Reporting eccentricity with units, or confusing it with c, the focal distance.

Don't do this: Write "e = 6 cm" or hand back c when asked for e.

The correct way: Eccentricity is a ratio of two lengths, so it has no units and is always a pure number between 0 and 1.

What to Remember About the Eccentricity of an Ellipse