Converse of Pythagoras Theorem - Proof and Examples
Converse of Pythagoras Theorem - Proof and Examples
What Is The Converse Of The Pythagoras Theorem?
The converse of the Pythagoras theorem states: in a triangle, if the square of the longest side equals the sum of the squares of the other two sides, then the triangle is a right triangle, with the right angle opposite that longest side. In symbols, if the sides are a, b, c with c the longest, and
a² + b² = c²
then the angle opposite c is 90°.
Proof Of the Converse
The converse is not obvious - knowing a² + b² = c² tells you about lengths, and the claim is about an angle. The proof bridges that gap by building a triangle we know is right-angled and showing the given one must match it.
Construct a brand-new right triangle PQR with a right angle at Q, legs PQ = a and QR = b.
By the forward Pythagoras theorem applied to PQR, its hypotenuse PR satisfies
PR² = a² + b².But we were given a² + b² = c², so
PR² = c² ⟹ PR = c.Now compare triangles ABC and PQR: all three sides match (a = a, b = b, and the third side c = PR). By the SSS (side-side-side) congruence rule, the two triangles are congruent.
Congruent triangles have equal corresponding angles, so the angle in ABC opposite c equals the angle in PQR opposite PR - which is the 90° we built. The triangle is right-angled.
The Test Also Sorts Acute And Obtuse Triangles
The converse does more than spot right triangles. Compare a² + b² with c² (where c is the longest side) and you can classify any triangle by its biggest angle:
- If a² + b² = c² → right triangle.
- If a² + b² > c² → acute triangle.
- If a² + b² < c² → obtuse triangle.
Examples of the Converse of the Pythagoras Theorem
Example 1
A triangle has sides 6, 8, and 10. Is it right-angled?
The longest side is 10, so test 6² + 8² against 10²:
6² + 8² = 36 + 64 = 100 = 10².
Final answer: yes, it is a right triangle.
Example 2
A triangle has sides 8, 10, and 6. A student computes 10² and compares it improperly. Is their conclusion correct?
They need to square the two shorter sides and compare against the longest:
6² + 8² = 100 = 10².
Final answer: it is a right triangle, as proven.
Example 3
Classify the triangle with sides 6, 8, and 11.
Longest side is 11.
Compare 6² + 8² with 11²:
6² + 8² = 36 + 64 = 100 < 121.
Final answer: an obtuse triangle.
Example 4
Classify the triangle with sides 4, 5, and 6.
Longest side is 6.
Compare 4² + 5² with 6²:
4² + 5² = 16 + 25 = 41 > 36.
Final answer: an acute triangle.
Example 5
A triangle has sides 5, 12, and 13. Show it is right-angled and name the hypotenuse.
Longest side is 13.
Test:
5² + 12² = 25 + 144 = 169 = 13².
Final answer: right-angled, hypotenuse = 13.
Example 6
A triangle has sides 9, 12, and 15. Is it right-angled?
Longest side is 15.
Compute:
9² + 12² = 81 + 144 = 225 = 15².
Final answer: yes, the corner is a true right angle.
The Mistakes Students Make Most Often On Converse
Mistake 1: Not identifying the longest side first
- Where it slips in: applying the converse improperly when sides are given in random order.
Mistake 2: Confusing the converse with the theorem
- Where it slips in: assuming given angles instead of checking with sides.
Mistake 3: Forgetting the acute and obtuse cases
- Where it slips in: stopping classification at non-right-angled conclusions.
Conclusion
- The converse of the Pythagoras theorem states that if a² + b² = c², the triangle is right-angled.
- It reverses the theorem.
- The proof shows the relationship between angles and sides accurately.