Integration of UV Formula — ∫u dv = uv − ∫v du
Integration of UV Formula — ∫u dv = uv − ∫v du
TL;DR
The integration of uv formula — integration by parts — is ∫u,dv=uv−∫v,du, the integration counterpart of the product rule for derivatives. This article derives it from the product rule, explains the ILATE rule for choosing u, works six examples in increasing difficulty (including the ∫lnx,dx trick), and shows the mistakes that turn a one-line problem into an endless loop.
A Formula for Products That Refuse to Integrate
Differentiating a product is easy — the product rule handles xsinx or xex in seconds. Integrating one is where students hit a wall, because there is no "product rule for integrals." The integration of uv formula is the closest thing: it doesn't integrate the product directly, it trades a hard integral for an easier one.
The integration of uv formula — also called integration by parts or the uv rule of integration — says:
∫u,dv = uv − ∫v,du
You split the integrand into a part u (which you'll differentiate) and a part dv (which you'll integrate), and the formula rewrites the original integral as a product minus a new integral — one you choose your split to make simpler.
What Is the Integration of UV Formula?
The integration of uv formula is the technique for integrating a product of two functions when no straightforward antiderivative exists. In its most-used form:
∫u,dv=uv−∫v,du
Here u and v are functions of x; you pick u and dv from the integrand, then compute du (by differentiating u) and v (by integrating dv). Written fully in terms of x:
∫u,w,dx=u∫w,dx−∫(u′∫w,dx)dx.
The point is never to integrate the product head-on. It is to swap the original integral for uv−∫v,du, where the new integral ∫v,du is simpler than the one you started with. Choose the split so that differentiating u shrinks it.
How Is the Integration of UV Formula Derived?
It comes straight from the product rule for derivatives. Start with two functions u and v:
ddx(uv) = u dv/dx + v du/dx.
Integrate both sides with respect to x. The left side integrates back to uv:
uv=∫u, dv/dx, dx + ∫v, du/dx, dx = ∫u, dv + ∫v, du.
Now rearrange to isolate the integral you want:
∫u,dv=uv−∫v,du.
That's the whole derivation. Integration by parts is the product rule run backwards and solved for one of its two integrals.
How Do You Choose u? The ILATE Rule
The formula only helps if the new integral ∫v,du is easier than the original. The choice of u decides that. The ILATE rule (also written LIATE) ranks function types by how good a choice they make for u — pick u from whichever type comes first:
| Priority | Type | Example |
|---|---|---|
| I | Inverse trigonometric | arctanx, arcsinx |
| L | Logarithmic | lnx, logx |
| A | Algebraic | x, x², polynomials |
| T | Trigonometric | sinx, cosx |
| E | Exponential | eⁿ, 2ˡ |
The logic: u should get simpler when differentiated, and dv should stay manageable when integrated. For ∫xlnx,dx, L beats A, so u=lnx.
Examples of the Integration of UV Formula
Example 1
Evaluate ∫x,eˣ,dx.
By ILATE, Algebraic (A) beats Exponential (E), so u=x and dv=eˣ,dx. Then du=dx and v=eˣ:
∫x,eˣ,dx=uv−∫v,du=x,eˣ−∫eˣ,dx=x,eˣ−eˣ+C.
Final answer: ∫x,eˣ,dx=eˣ(x−1)+C.
Example 2
Evaluate ∫xcosx,dx.
Let u=x (Algebraic) and dv=cosx,dx. Then du=dx and v=sinx:
∫xcosx,dx=xsinx−∫sinx,dx=xsinx+cosx+C.
Final answer: ∫xcosx,dx=xsinx+cosx+C.
Example 3
Evaluate ∫x²lnx,dx.
By ILATE, Logarithmic (L) beats Algebraic (A), so u=lnx and dv=x²,dx. Then du=rac{1}{x},dx and v=rac{x³}{3}:
∫x²lnx,dx=rac{x³}{3}lnx−rac{1}{3}∫x²,dx.
Final answer: ∫x²lnx,dx=rac{x³}{3}lnx−rac{x³}{9}+C.
Example 4
Evaluate ∫lnx,dx.
Let u=lnx and dv=1,dx. Then du=rac{1}{x},dx and v=x:
∫lnx,dx=xlnx−x+C.
Final answer: ∫lnx,dx=xlnx−x+C.
Example 5
Evaluate ∫arctanx,dx.
Let u=arctanx and dv=1,dx; then du=rac{1}{1+x²},dx and v=x:
∫arctanx,dx=xarctanx−rac{1}{2} ext{ln}(1+x²)+C.
Final answer: ∫arctanx,dx=xarctanx−rac{1}{2} ext{ln}(1+x²)+C.
Example 6
Evaluate ∫eˣsinx,dx.
Let I=∫eˣsinx,dx and let u=sinx, dv=eˣ,dx:
I=eˣsinx−∫eˣcosx,dx.
Apply parts again to ∫eˣcosx,dx with the same steps returning to I yields:
Final answer: ∫eˣsinx,dx=rac{eˣ(sinx−cosx)}{2}+C.
Where the Integration of UV Formula Carries Real Weight
- Physics — quantum mechanics.
- Signal processing — the Fourier and Laplace transforms.
- Probability and statistics.
- Engineering — the weak form of differential equations.
Tripping Points to Avoid
Mistake 1: Choosing u and dv backwards
Mistake 2: Dropping the minus sign before the second integral
Mistake 3: Forgetting the constant of integration
Conclusion
- The integration of uv formula is ∫u,dv=uv−∫v,du.
- It is derived by integrating the product rule and solving for one integral.
- Use the ILATE rule to choose u so the new integral is simpler.
- The pairing-with-1 trick integrates functions like lnx and arctanx.
- Most common errors include choosing u and dv backwards, dropping the minus sign, and forgetting +C.
Practice These Before Moving On
- Evaluate ∫xsinx,dx.
- Evaluate ∫x,lnx,dx.
- Evaluate ∫eˣcosx,dx using the loop method.