Factorization of Quadratic Polynomials - Methods
Factorization of Quadratic Polynomials - Methods
TL;DR
Factorizing a quadratic polynomial ( ax^2 + bx + c ) means rewriting it as a product of two linear factors, usually by splitting the middle term so the two pieces multiply to ( ac ) and add to ( b ). This article covers four methods, six worked examples, and the sign errors that derail most attempts.
What Does It Mean to Factorize a Quadratic Polynomial?
Factorizing a quadratic polynomial means expressing ( ax^2 + bx + c ) as a product of two linear factors of the form ( (px+q)(rx+s) ). When the quadratic equals zero, those factors provide the roots directly.
If ( ax^2 + bx + c = (x-h)(x-k) ), then ( h ) and ( k ) are the roots of the quadratic. Not every quadratic factors neatly over the rational numbers. When it does not, the quadratic formula still finds the roots.
How Do You Factorize a Quadratic Polynomial?
There are four standard methods:
- Splitting the middle term: Find two numbers that multiply to ( ac ) and add to ( b ).
- Algebraic identities: When the quadratic is a perfect square trinomial or a difference of squares.
- Grouping: Useful when a common factor appears in pairs.
- The quadratic formula: When no clean factors exist.
Splitting the middle term, step by step
For ( ax^2 + bx + c ), find two numbers whose product is ( a \times c ) and whose sum is ( b ).
- Compute ( ac ).
- Find two numbers multiplying to ( ac ) and adding to ( b ).
- Split the middle term.
- Group and factor each pair.
- Factor out the common bracket.
Examples of Factorization of Quadratic Polynomials
Example 1: Factorize ( x^2 + 8x + 15 )
- ( ac = 1 \times 15 = 15 )
- Two numbers are 3 and 5.
- Split: ( x^2 + 3x + 5x + 15 )
- Group: ( x(x+3) + 5(x+3) )
- Factor: ( (x+3)(x+5) )
Final answer: ( (x+3)(x+5) )
Example 2: Factorize ( x^2 - 2x - 15 )
- Product is ( -15 ) and sum is ( -2 ).
- Correct numbers are -5 and 3.
- Split: ( x^2 - 5x + 3x - 15 )
- Group: ( x(x - 5) + 3(x - 5) )
- Factor: ( (x - 5)(x + 3) )
Final answer: ( (x-5)(x+3) )
Example 3: Factorize ( 6x^2 - 5x - 6 )
- ( ac = 6 \times (-6) = -36 )
- Numbers are -9 and +4.
- Split: ( 6x^2 - 9x + 4x - 6 )
- Group: ( 3x(2x - 3) + 2(2x - 3) )
- Factor: ( (2x - 3)(3x + 2) )
Final answer: ( (2x-3)(3x+2) )
Common Mistakes in Factorization
- Getting the signs of the two numbers backwards. Check both conditions: product equals ( ac ) and sum equals ( b ).
- Forgetting the leading coefficient when ( a \neq 1). Always use ( a \times c ) as the product target.
- Assuming every quadratic factors over the rationals. Check the discriminant.
Practice Questions on Factorization of Quadratic Polynomials
- Factorize ( x^2 + 7x + 12 ).
- Factorize ( x^2 - x - 12 ).
- Factorize ( 2x^2 + 7x + 3 ).
- Factorize ( x^2 - 14x + 49 ).
- Factorize ( 25x^2 - 9 ).
- Factorize ( 3x^2 + 5x - 4 ).
Answers
- ( (x+3)(x+4) )
- ( (x-4)(x+3) )
- ( (2x+1)(x+3) )
- ( (x-7)^2 )
- ( (5x+3)(5x-3) )
- No rational factors; roots are ( x = \frac{-1 \pm \sqrt{13}}{3} ).
Key Takeaways
- Factorization rewrites ( ax^2 + bx + c ) as a product of two linear factors.
- Splitting the middle term is the main method.
- Perfect square trinomials and differences of squares factor instantly via identities.
- If no rational factors exist, use the quadratic formula while checking the discriminant first.