Elimination Method — Steps and Worked Examples

Elimination Method — Steps and Worked Examples

What Is The Elimination Method?

The elimination method is a way to solve a system of equations by combining the equations so that one variable is removed. You add or subtract the equations to cancel a variable, solve the resulting one-variable equation, then substitute back to find the other variable. It is also called the addition method.

It works because adding equal things to equal things keeps an equation true: if a=ba = ba=b and c=dc = dc=d, then a+c=b+da + c = b + da+c=b+d. Cancelling a variable is just a clever choice of what to add.

When do you add, and when do you subtract?

The decision rests on the coefficients of the variable you want to remove.

If neither matches, you first multiply one or both equations by a constant to make a pair match. That scaling step is the heart of the method.

The Steps Of The Elimination Method

Step What you do
1 Write both equations in standard form ax+by=c, lined up by variable.
2 Multiply one or both equations so one variable has matching or opposite coefficients.
3 Add (opposite coefficients) or subtract (equal coefficients) to eliminate that variable.
4 Solve the resulting single-variable equation.
5 Substitute that value back into either original equation to find the other variable.
6 Check the pair in both original equations.

Examples Of The Elimination Method

Example 1

Solve:
x+y=7
x−y=3
The y coefficients are opposites (+1 and −1), so add the equations:

2x=10
x=5
Substitute into the first equation:
5+y=7
y=2
Final answer: (5,2).

Example 2

Solve:
3x+2y=16
3x−y=4
The x coefficients are equal (3 and 3). The first instinct is to add the equations — but watch what adding does:
6x+y=20
Both variables survived; nothing was eliminated. The fix is to subtract:

(3x+2y)−(3x−y)=16−4
3y=12
y=4
Substitute into the second equation:
3x−4=4
x=8
Final answer: (8, 4).

Example 3

Solve (coefficients must be scaled first):
2x+3y=13
4x−y=5
Multiply the second equation by 3 so the y terms become opposites:

2x+3y=13
6x−3y=15
Now add:

8x=28
x=2
Substitute into the second original equation:

4(2)−y=5
y=3
Final answer: (2,3).

Example 4

Solve (scale both equations):
3x+4y=10
2x+5y=9
To cancel x, multiply the first by 2 and the second by 3:

6x+8y=20
6x+15y=27
Subtract:
7y=7
y=1
Substitute into 3x+4y=10:

3x+4=10
x=2
Final answer: (2,1).

Example 5

A no-solution case:
2x+3y=12
4x+6y=30
Multiply the first by 2 to match the x coefficients:

4x+6y=24
Subtract: 0=−6
Final answer: no solution (inconsistent system).

Example 6

Two numbers have a sum of 9 and a difference of 5. Find them. Let the numbers be x and y:

x+y=9
x−y=5
Add to cancel y:

2x=14
x=7
y=2
Final answer: the numbers are 7 and 2.

Why The Elimination Method Earns Its Place

The reason to reach for elimination is that it stays clean where other methods get messy.

Where Students Lose The Mark On Elimination

Mistake 1: Adding when you should subtract (or vice versa)

The correct way: Equal coefficients cancel on subtraction; opposite coefficients cancel on addition.

Mistake 2: Sign errors when subtracting

The correct way: Distribute the minus across every term: rewrite the subtracted equation with all signs flipped first, then add.

Mistake 3: Forgetting to back-substitute, or substituting into the scaled equation

The correct way: After solving for one variable, substitute back into one of the original equations to find the other.

Conclusion

Practice Questions on the Elimination Method

  1. By adding: x+y=10 and x−y=4.
  2. By subtracting: 2x+y=7 and 2x+3y=11.
  3. By scaling first: 3x+2y=7 and 5x+4y=13.
  4. Classify: 2x+3y=12 and 4x+6y=18.

Answers

  1. Final answer: (7,3).
  2. Final answer: (2,2).
  3. Final answer: (1,2).
  4. Final answer: no solution.